This quiz works best with JavaScript enabled. Home > Class 12 > Class 12 Biology Chapter 5 Principles Of Inheritance And Variation – Quiz 3 🏠 Homepage 📘 Download PDF Books 📕 Premium PDF Books Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 3 (25 MCQs) Quiz Instructions Select an option to see the correct answer instantly. 1. The syndrome in which individual somatic cell contains 3 sex chromosomes XXX Is called A) Klinefelters syndrome. B) Turner syndrome. C) Downs syndrome. D) Super female. Show Answer Correct Answer: D) Super female. 2. Sickle-cell anaemia is a classical example of A) Frame-shift mutation. B) Point mutation. C) Both (a) and (b). D) None of the above. Show Answer Correct Answer: B) Point mutation. 3. Mendel's Law of independent assortment holds good for genes situatedon the: A) Non-homologous chromosomes. B) Homologous chromosomes. C) Extra nuclear genetic element. D) Same chromosome. Show Answer Correct Answer: A) Non-homologous chromosomes. 4. In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with green seeded plant, what ratio of yellow and green seeded plants would you expect in F$_{1}$-generation. A) 50:50. B) 9:1. C) 1:3. D) 3:1. Show Answer Correct Answer: A) 50:50. 5. Gene A and B are linked and 12 map units apart. A heterozygous individual, whose parents were AAbb and aaBB, would be expected to produce gamete in the following frequencies- A) 44% AB, 6% Ab, 6% aB, 44% ab. B) 6% AB, 44% Ab, 44% aB, 6% ab. C) 12% AB, 38% Ab, 38% aB, 12% ab. D) 6% AB, 6% Ab, 44% aB, 44% ab. Show Answer Correct Answer: B) 6% AB, 44% Ab, 44% aB, 6% ab. 6. In fruit flies, long wing is dominant to vestigial wing. When heterozygous long-winged flies were crossed with vestigial-winged flies, 192 offsprings were produced. If an exact Mendelian ratio had been obtained, then the number of each phenotype would have been A) Long-winged 64 Vestigial-winged 128. B) Long-winged 96 Vestigial-winged 96. C) Long-winged 128 Vestigial-winged 64. D) Long-winged 192 Vestigial-winged 0. Show Answer Correct Answer: B) Long-winged 96 Vestigial-winged 96. 7. ONE TRAIT CAN BE INFLUENCED BY MORE THAN ONE GENES, THIS IS THE CASE OF A) PLEIOTROPY. B) POLYGENIC INHERITANCE. C) CODOMINANCE. D) ALL OF THE ABOVE. Show Answer Correct Answer: B) POLYGENIC INHERITANCE. 8. Cystic fibrosis is A) Sex-linked recessive disorder. B) Sex-linked dominant disorder. C) Autosomal dominant disorder. D) Autosomal recessive disorder. Show Answer Correct Answer: D) Autosomal recessive disorder. 9. Mutation due to Change in a single base pair of DNA is- A) Frame shift eg.Sickle Cell Anaemia. B) Point, eg.Sickle Cell Anaemia. C) Point, eg.Down's Syndrome. D) Frame shift, eg.Down's Syndrome. Show Answer Correct Answer: B) Point, eg.Sickle Cell Anaemia. 10. A man having the genotype EEFfGgHH can produce P number of genetically different sperms, and a woman of genotype IiLLMmNn can generate Q number of genetically different eggs. Determine the values of P and Q. A) P=4, Q=4. B) P=4, Q=8. C) P=8, Q=4. D) P=8, Q=8. Show Answer Correct Answer: B) P=4, Q=8. 11. The cause(s) for mendelian disorders is/are A) Aneuploidy. B) Polyploidy. C) Alteration in single gene. D) Both a and b. Show Answer Correct Answer: C) Alteration in single gene. 12. Gynaecomastia condition is result of- A) Down's Syndrome. B) Turner's Syndrome. C) Klinefelter's Syndrome. D) Edward's Syndrome. Show Answer Correct Answer: C) Klinefelter's Syndrome. 13. If the father is haemophilic and mother is normal, then the daughter will have chance to A) Be haemophilic. B) Be carrier of haemophilia. C) Be normal always. D) Not receive any gene of haemophilia any time. Show Answer Correct Answer: B) Be carrier of haemophilia. 14. Bateson used the terms coupling and repulsion for linkage and crossing over. Name the correct parental or coupling type along with its cross over or repulsion: A) Coupling aaBB, aabb; Repulsion AABB, aabb. B) Coupling AABB, aabb; Repulsion AABB, AAbb. C) Coupling AAbb, aaBB; Repulsion AaBb, aabb. D) Coupling AABB, aabb; Repulsion AAbb, aaBB. Show Answer Correct Answer: D) Coupling AABB, aabb; Repulsion AAbb, aaBB. 15. It is said that Mendel proposed that the factor controlling any characteris discrete and independent. His proposition was based on the A) Results of F3 generation of a cross. B) Observations that the offspring of a cross made between the plants having two contrasting characters shows only one character without any blending. C) Self pollination of F1 offsprings. D) Cross pollination of F1 generation with recessive parent. Show Answer Correct Answer: B) Observations that the offspring of a cross made between the plants having two contrasting characters shows only one character without any blending. 16. Which of the following is/are possible for a modified allele? A) Can produce no enzyme. B) Can produce a non-functional enzyme. C) Can produce an altered and functional product. D) All (i), (ii) & (iii). Show Answer Correct Answer: D) All (i), (ii) & (iii). 17. The linkage group(s) of a human sperm and egg is A) 23 each. B) 24 and 23 respectively. C) 23 and 24 respectively. D) 22 and 23 respectively. Show Answer Correct Answer: A) 23 each. 18. A tobacco plant heterozygous for a recessive character is self-pollinated and 1200 seeds are subsequently germinated. How many seedlings would have the parental genotype? A) 120. B) 600. C) 300. D) 750. Show Answer Correct Answer: B) 600. 19. Experimental verification of 'chromosomal theory of inheritance' was done by A) Sutton and Boveri. B) Morgan et al. C) Henking. D) Karl Correns. Show Answer Correct Answer: B) Morgan et al. 20. A couple has six daughters. What is the possibility of their having a girl next time? A) 10%. B) 50%. C) 90%. D) 100%. Show Answer Correct Answer: B) 50%. 21. What is the expected outcome of a test cross? A) To determine the genotype of an individual with a dominant phenotype. B) To create a new hybrid organism. C) To identify linked genes. D) To analyze a pedigree chart. Show Answer Correct Answer: A) To determine the genotype of an individual with a dominant phenotype. 22. THERE ARE 6 GENOTYPES TO REPRESENT 4 BLOOD GROUPS IN HUMAN BEINGS.WHICH ONE OF THE FOLLOWING GENOTYPES SHOWS CODOMINANCE A) I$^{A}$I$^{A}$. B) I$^{B}$I$^{B}$. C) I$^{A}$I. D) I$^{A}$I$^{B}$. Show Answer Correct Answer: D) I$^{A}$I$^{B}$. 23. An affected female shows following symptomsi.Rudimentary ovaries ii.Sterility iii.Lack of secondary sexual charactersThe affected female is diagnosed with A) Klinefelter's syndrome. B) Cystic fibrosis. C) Turner's syndrome. D) Phenylketonuria. Show Answer Correct Answer: C) Turner's syndrome. 24. It is used to stop the cell division at metaphase of karyotyping. A) Renin. B) Colchicine. C) Sebum. D) Melatonin. Show Answer Correct Answer: B) Colchicine. 25. A human female with Turner's syndrome A) Has 45 chromosomes with XO. B) Has one additional X-chromosome. C) Exhibits male characters. D) Is able to produce children with normal husband. Show Answer Correct Answer: A) Has 45 chromosomes with XO. ← PreviousNext →Related QuizzesClass 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 1Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 2Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 4Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 5Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 6Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 7Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 8Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 9Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 10Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Quiz 11 🏠 Back to Homepage 📘 Download PDF Books 📕 Premium PDF Books