This quiz works best with JavaScript enabled. Home > Class 12 > Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements – Quiz 18 🏠 Homepage 📘 Download PDF Books 📕 Premium PDF Books Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 18 (25 MCQs) Quiz Instructions Select an option to see the correct answer instantly. 1. Total number of lone pair of electrons in XeOF$_{4}$ is A) 0. B) 1. C) 2. D) 3. Show Answer Correct Answer: B) 1. 2. What is the molecular geometry of SF$_{4 }$ A) Tetrahedral. B) Seesaw. C) Tetragonal. D) Square planar. Show Answer Correct Answer: B) Seesaw. 3. Nitrogen always acquires-3 oxidation state by sharing of electrons while other elements do so by gaining of electrons. A) True. B) False. C) All the above. D) None of the above. Show Answer Correct Answer: B) False. 4. Which is the most abundant element on the earth's crust among group 15 elements A) Phosphorous. B) Astatine. C) Neon. D) Helium. Show Answer Correct Answer: A) Phosphorous. 5. Which one of the following is not an use of ammonia? A) To produce various nitrogenous fertilizers. B) In manufacture of nitric acid. C) As a refrigerate. D) In the pickling of stainless steel. Show Answer Correct Answer: D) In the pickling of stainless steel. 6. Which of the following is incorrect with respect to the property mentioned? A) HF < HCI < HBr < HI (Acidic strength). B) HF > HCI > HBr > HI (Stability). C) HF > HCI > HBr > HI (Boiling point). D) HF < HCI < HBr < HI (Reducing nature). Show Answer Correct Answer: C) HF > HCI > HBr > HI (Boiling point). 7. Nitrogen cannot exhibit co valancy more than four due to A) Presence of vacant d orbitals. B) Due to large size. C) Due to absence of vacant d orbitals. D) Due to inert nature. Show Answer Correct Answer: C) Due to absence of vacant d orbitals. 8. Which property of halogens increases from fluorine to iodine A) Melting point. B) Ionization energy. C) Atomic size. D) Electronegativity. Show Answer Correct Answer: C) Atomic size. 9. Which of the following elements belongs to Group 17? A) Argon. B) Chlorine. C) Sulphur. D) Aluminium. Show Answer Correct Answer: B) Chlorine. 10. Anomalous behavior of Be is due to: A) Small size and high charge density. B) Its metallic nature. C) High electronegativity. D) Presence of unpaired electrons. Show Answer Correct Answer: A) Small size and high charge density. 11. Borazine is also called: A) Boron hydride. B) Inorganic benzene. C) Hydrated borax. D) Alumina. Show Answer Correct Answer: B) Inorganic benzene. 12. Basicity of hydrides of N family follows theorder. A) NH$_{3}$ < PH$_{3}$ < AsH$_{3}$ < SbH$_{3}$ < BiH$_{3}$. B) NH$_{3}$ < PH$_{3}$ < AsH$_{3}$ > SbH$_{3}$ > BiH$_{3}$. C) NH$_{3}$ > PH$_{3}$ > AsH$_{3}$ > SbH$_{3}$ > BiH$_{3}$. D) NH$_{3}$ = PH$_{3}$ = AsH$_{3}$ = SbH$_{3}$ = BiH$_{3}$. Show Answer Correct Answer: C) NH$_{3}$ > PH$_{3}$ > AsH$_{3}$ > SbH$_{3}$ > BiH$_{3}$. 13. Which statement about carbon and silicon is correct? A) They have the same electronegativity. B) Both can form giant covalent structures. C) Silicon is more reactive than carbon. D) Carbon always forms ionic compounds. Show Answer Correct Answer: B) Both can form giant covalent structures. 14. What is the significance of the P block in the periodic table? A) The P block is primarily made up of radioactive elements. B) The P block is significant for its diverse elements that are essential for life, chemical bonding, and various industrial applications. C) The P block contains only metals that are not used in industry. D) The P block is significant for its role in nuclear reactions. Show Answer Correct Answer: B) The P block is significant for its diverse elements that are essential for life, chemical bonding, and various industrial applications. 15. When diborane is subjected to methylation, how many hydrogens are methylated in diborane? A) 3. B) 2. C) 4. D) 6. Show Answer Correct Answer: C) 4. 16. Which of the following elements can be involved inpp-dp bonding? A) (A) Carbon. B) (B) Nitrogen. C) (C) Phosphorus. D) D) Boron. Show Answer Correct Answer: C) (C) Phosphorus. 17. What did Haber synthesis is for? A) Synthesizing Chlorine gas. B) Synthesizing Mustard gas. C) Synthesizing Ammonia. D) Synthesizing Sulphuric acid. Show Answer Correct Answer: C) Synthesizing Ammonia. 18. Chlorine react with cold sodium hydroxide solution. Which of the chemical equation shows the reaction? A) Cl$_{2}$(g)+ NaOH(aq) => NaOCl(aq) +HCl(aq). B) Cl$_{2}$(g)+ 2NaOH(aq) => NaOCl(aq) +H$_{2}$(g) +O$_{2}$(g). C) 2Cl$_{2}$(g)+ 4NaOH(aq) => 4NaCl(aq) +2H$_{2}$O(l) +O$_{2}$(g). D) Cl$_{2}$(g)+ 2NaOH(aq) => NaCl(aq) +NaOCl(aq) +H$_{2}$O(l). Show Answer Correct Answer: D) Cl$_{2}$(g)+ 2NaOH(aq) => NaCl(aq) +NaOCl(aq) +H$_{2}$O(l). 19. A brown ring is formed in the ring test for NO3-ion. It is due to the formation of: A) [Fe(H2O)5(NO)]2+. B) FeSO4.NO2. C) [Fe(H2O)4(NO)2]2+. D) FeSO4.HNO3. Show Answer Correct Answer: A) [Fe(H2O)5(NO)]2+. 20. Which of the following physical properties describe Group 18 elements? A) Group 18 elements generally exists as liquid in room temperature. B) Group 18 elements generally has high melting point. C) Group 18 elements are reactive towards oxygen gas, O$_{2}$. D) Group 18 elements generally has low boiling point. Show Answer Correct Answer: D) Group 18 elements generally has low boiling point. 21. Ammonia is liquid while phosphine is a gas . Why? A) Due to more molar mass ammonia has maximum van der wall force of attraction. B) Due to more molar mass, ammonia has less van der wall force of attraction. C) Due to the presence of inter molecular hydrogen bonding in ammonia. D) Due to the absence of hydrogen bonding in ammonia. Show Answer Correct Answer: C) Due to the presence of inter molecular hydrogen bonding in ammonia. 22. No. of lone pairs and type of hybridization in "S" in SO$_{3}$ molecule are respectively A) 0 and sp$^{2}$. B) 1 and sp$^{2}$. C) 0 and sp$^{3}$. D) 1 and sp$^{3}$. Show Answer Correct Answer: A) 0 and sp$^{2}$. 23. In p-block, non-metals are placed in A) Upper right part. B) Middle part. C) Lower left part. D) Bottom of the group. Show Answer Correct Answer: A) Upper right part. 24. The brown ring test for nitrates depends upon A) The reduction of nitrate to nitric oxide. B) Oxidation of nitric oxide to nitrogen dioxide. C) Reduction of ferrous sulphate to iron. D) Oxidising action of sulphuric acid. Show Answer Correct Answer: A) The reduction of nitrate to nitric oxide. 25. Which of the following is one of the rarest elements of group 18? A) Helium. B) Xenon. C) Krypton. D) Neon. Show Answer Correct Answer: B) Xenon. ← PreviousNext →Related QuizzesClass 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 1Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 2Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 3Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 4Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 5Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 6Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 7Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 8Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 9Class 12 Chemistry (Part Ii) Chapter 7 P Block Elements Quiz 10 🏠 Back to Homepage 📘 Download PDF Books 📕 Premium PDF Books